已解決bat腳本中如何顯示正在運行的程序數(shù)量最后由 xfgc 于 -4-25 15:49各位大佬們，想咨詢一下，bat是否能實現(xiàn)如下功能，1.計算正在運行的特定程序的數(shù)量；2.當運行程序的數(shù)量小于某一值（比如 40 ）時，自動運行下一個程序，直到滿足運行程序的數(shù)量為40

@echo off
setlocal enabledelayedexpansion
call fds
set filnavn1=1.fds
set mappenavn1=1
set path1=%mappenavn1%
set filnavn2=2.fds
set mappenavn2=2
set path2=%mappenavn2%
set filnavn3=3.fds
set mappenavn3=3
set path3=%mappenavn3%
set filnavn4=4.fds
set mappenavn4=4
set path4=%mappenavn4%
if not exist %path1% mkdir %path1%
copy %filnavn1% %path1%
if not exist %path2% mkdir %path2%
copy %filnavn2% %path2%
if not exist %path3% mkdir %path3%
copy %filnavn3% %path3%
if not exist %path4% mkdir %path4%
copy %filnavn4% %path4%
cd %mappenavn1%
start cmd /k call fds_local -p 4 %filnavn1%
cd..
cd %mappenavn2%
start cmd /k call fds_local -p 4 %filnavn2%
cd..
rem 定義包含 fds 文件的文件夾列表
set folders=Folder1 Folder2 Folder3 Folder4
REM 設置特定程序名稱
set program_name=fds.exe
REM 設置計數(shù)器
set /a count=0
REM 遍歷 tasklist 輸出的每一行
for /f skip=3 tokens=1 %%a in ('tasklist ^| findstr /i /c:%program_name%') do (
REM 如果行不為空，則增加計數(shù)器
if not %%a== (
set /a count+=1
)
)
REM 如果特定程序的數(shù)量小于8，則啟動下一個程序
if %count% LSS 8 (
 rem 獲取下一個未運行的 fds 文件
for %%i in (%folders%) do (
cd %%i
for %%j in (%fds_files%) do (
tasklist| findstr /i fds.exe > nul
if errorlevel 1 (
rem 啟動下一個 fds 文件任務
start cmd /c call fds_local -p 4 %%i.fds
goto :next_file
)
)
cd ..
)
)
:next_file
rem 等待一段時間后繼續(xù)檢查
timeout /t 5
goto start
rem 如果沒有正在運行的 fds，則顯示 All simulations completed. 并暫停腳本
echo All simulations completed.
pause
exit
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