【已解決】這段批處理代碼為什么不正確最后由 chouxia 于 -10-28 08:17

@echo on
setlocal enabledelayedexpansion
set num=0
set inipath=0
set dataname=0
cd v:1data
for /f %%z in ('findstr /s /i /m data=1 *.txt') do (
for /f tokens=1,* delims==%%a in ('find num ^< %%z') do ( set num=%%b )
for /f tokens=1,* delims==%%c in ('find inipath ^< %%z') do ( set inipath=%%d )
for /f tokens=1,* delims==%%g in ('find dataname ^< %%z') do ( set dataname=%%h )
echo NO.0!num!!inipath! !dataname!
for /l %%i in (1,1,!num!) do (
if not exist v:!inipath!work_%%i.avi 
echo ok
if exist v:!inipath!work_%%i.avi
echo n-----ok
)
)
nclick="copycode($('code0'));">復制代碼

執行的時候提示我語法不正確if not exist v:!inipath!work_%i.avi而且 echo NO.0 !num!!inipath!!dataname!這行根本沒顯示變量!num!為何沒有數據？執行到echo NO.0 !num!!inipath!!dataname!截止既：后面的forindo 都不在的話輸出內容如下：NO. 0 5 1temp1007183419010016h 1007183419010016hNO. 0 5 1temp1007183419010016s 1007183419010016sNO. 0 5 1temp1007183419060016h 1007183419060016hNO. 0 5 1temp1007183419060016s 1007183419060016s