
[已解決]求助批處理把多個(gè)ASC文件合并從每個(gè)文件的第3行開始最后由 xueyufei 于 -3-12 11:54求助各位大佬~我要寫一個(gè)*.bat的代碼,實(shí)現(xiàn)以下作用:1、有個(gè)多個(gè)asc格式的文件(相當(dāng)于txt),按文件名排序2、使用 bat代碼對(duì)多個(gè)asc文件進(jìn)行合并,要求為:2.1 第一個(gè)asc文件,從第一行開始復(fù)制2.2 其余的asc文件,從第三行開始復(fù)制2.3 如果以上兩個(gè)條件很難同時(shí)實(shí)現(xiàn),那就:所有文件都從第三行開始復(fù)制3、合并后的文件,在根目錄下,重命名為“合并.asc”例如:第一個(gè)文件:20-35.asc------------------date Sunday Mar 11 20:35:00 base hextimestamps absolute74099.2804 2 0C0000E4x Rx d 871 20 1C 00 FF 00 FF FF74099.2807 1 00000280x Rx d 800 00 15 00 7F 00 37 0174099.2811 2 0CF00300x Rx d 8FA FE 00 00 FF FF FF FF------------------第二個(gè)文件:20-36.asc------------------date Sunday Mar 11 20:36:00 base hextimestamps absolute74159.2757 2 18FED900x Rx d 800 00 0C 0F 3F 00 0C 0174159.2763 1 18F00E00x Rx d 800 00 00 00 00 00 00 0074159.2763 2 18F00A00x Rx d 8FF FF 00 00 FF FF FF FF74159.2768 1 00000074x Rx d 8CE 13 00 00 00 00 00 0074159.2769 2 18FEDF00x Rx d 881 FF FF FF 00 00 00 00------------------第三個(gè)文件:20-37.asc------------------date Sunday Mar 11 20:37:00 base hextimestamps absolute74219.2712 1 000001B4x Rx d 800 00 00 00 00 00 00 0074219.2718 1 18EB0000x Rx d 800 A0 00 00 00 00 00 A874219.2724 1 0C41A800x Rx d 800 00 00 00 00 00 00 0074219.2730 1 0C41A804x Rx d 800 00 00 00 00 00 00 00------------------合并的結(jié)果:合并.asc------------------date Sunday Mar 11 20:35:00 base hextimestamps absolute74099.2804 2 0C0000E4x Rx d 871 20 1C 00 FF 00 FF FF74099.2807 1 00000280x Rx d 800 00 15 00 7F 00 37 0174099.2811 2 0CF00300x Rx d 8FA FE 00 00 FF FF FF FF74159.2757 2 18FED900x Rx d 800 00 0C 0F 3F 00 0C 0174159.2763 1 18F00E00x Rx d 800 00 00 00 00 00 00 0074159.2763 2 18F00A00x Rx d 8FF FF 00 00 FF FF FF FF74159.2768 1 00000074x Rx d 8CE 13 00 00 00 00 00 0074159.2769 2 18FEDF00x Rx d 881 FF FF FF 00 00 00 0074219.2712 1 000001B4x Rx d 800 00 00 00 00 00 00 0074219.2718 1 18EB0000x Rx d 800 A0 00 00 00 00 00 A874219.2724 1 0C41A800x Rx d 800 00 00 00 00 00 00 0074219.2730 1 0C41A804x Rx d 800 00 00 00 00 00 00 00------------------如果很難實(shí)現(xiàn),就都從第三行開始復(fù)制,合并結(jié)果合并的結(jié)果:合并.asc------------------74099.2804 2 0C0000E4x Rx d 871 20 1C 00 FF 00 FF FF74099.2807 1 00000280x Rx d 800 00 15 00 7F 00 37 0174099.2811 2 0CF00300x Rx d 8FA FE 00 00 FF FF FF FF74159.2757 2 18FED900x Rx d 800 00 0C 0F 3F 00 0C 0174159.2763 1 18F00E00x Rx d 800 00 00 00 00 00 00 0074159.2763 2 18F00A00x Rx d 8FF FF 00 00 FF FF FF FF74159.2768 1 00000074x Rx d 8CE 13 00 00 00 00 00 0074159.2769 2 18FEDF00x Rx d 881 FF FF FF 00 00 00 0074219.2712 1 000001B4x Rx d 800 00 00 00 00 00 00 0074219.2718 1 18EB0000x Rx d 800 A0 00 00 00 00 00 A874219.2724 1 0C41A800x Rx d 800 00 00 00 00 00 00 0074219.2730 1 0C41A804x Rx d 800 00 00 00 00 00 00 00------------------補(bǔ)充說(shuō)明:文件數(shù)量很多,每個(gè)文件里的行數(shù)也很多!#每分鐘一個(gè)文件,即一天有60*24=1440個(gè)文件#每個(gè)文件,有3-5萬(wàn)行

